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Mathematical proof

Revision notes · spec Prf1-Prf4

Section 2: Mathematical reasoning (Paper 2 only)

Recognise the four proof types the spec names - direct deduction, cases, contradiction, disproof by counterexample - and be able to reorder a scrambled proof, spot a circular argument, and justify a conjecture made from small cases with a general argument.

Proof types (Prf1)

  • Direct: start from what is given and deduce step by step ('\(n(n + 1)\) is a product of consecutive integers, so it is even').
  • Cases: split by parity, by remainder mod \(3\), by sign; the cases must cover everything.
  • Contradiction: assume the statement is false (the hypothesis true and the conclusion false), derive an impossibility. Classic: \(\sqrt2\) irrational, infinitely many primes.
  • Counterexample: one instance with the hypothesis true and the conclusion false disproves a 'for all' claim; it says nothing about an 'exists' claim.
  • Checking small cases (\(n^2 - n + 41\) is prime for \(n = 1, \ldots, 40\) but not \(41\)) is evidence, not proof.

Working with proofs (Prf2-Prf4)

  • Ordering steps: the assumption comes first, the contradiction last; each line must use only earlier lines.
  • Deducing from given implications: use the contrapositive ('\(f(x) > 0 \Rightarrow g(x) > 0\) and \(g(2) = -1\)' gives \(f(2) \leq 0\)).
  • Backwards working (start from the result, reach a truth) is valid only if every step is reversible and the proof is then presented forwards.
  • Conjecture from a pattern, then justify algebraically: \(T_n + T_{n+1} = (n + 1)^2\) by expanding.
  • A proof for \(\sqrt2\) copied for \(\sqrt4\) breaks where the parity argument no longer applies - identify which step fails.

Must-know (no formula booklet)

  • counterexample: hypothesis true, conclusion false
  • contradiction: assume not-conclusion
  • cases must be exhaustive
  • small cases \(\neq\) proof

Classic traps

  • 'If \(x^2 > 9\) then \(x > 3\)' is false: \(x = -4\). Taking square roots loses the negative branch.
  • Assuming the claim to prove the claim is circular even if every step 'works'.
  • An 'exists' statement cannot be disproved by a counterexample; it needs a proof that no example exists.

Worked example

Q. Prove: if \(n^2\) is even then \(n\) is even.

A. Contrapositive: if \(n\) is odd, \(n = 2k + 1\), then \(n^2 = 4k^2 + 4k + 1\) is odd.

How it has been examined

2023 · Paper 2Question 3claim about sqrt(xy) = sqrt(x)sqrt(y)question papersit online
2022 · Paper 2Question 3counterexample: n prime, n^2 + 2 not primequestion papersit online
2021 · Paper 2Question 4counterexample: a divides bcquestion papersit online
2020 · Paper 2Question 4N > 6 as a sum of two non-primesquestion papersit online
2019 · Paper 2Question 4conjecture about 10...01 being primequestion papersit online
2019 · Paper 2Question 7counterexample from 12^2 + 16^2 = 20^2question papersit online
October 2018 · Paper 2Question 6counterexample: f' > 0 but f not positivequestion papersit online
October 2018 · Paper 2Question 12N(Km + 1) - 1 is never primequestion papersit online
November 2017 · Paper 2Question 591 = 7 x 13 as a counterexamplequestion papersit online
Practice papers · Paper 2Question 5counting counterexamples to a primality claimquestion papersit online
Practice papers · Paper 2Question 7ordering the lines of a logarithm proofquestion papersit online
Specimen papers · Paper 2Question 8sum of four consecutive integers is a multiple of 6question papersit online